Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has 7 sweets left. How many did he have to start with?
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Step-by-step explanation:
Let the total number of sweets with Sekhar be x.
He gave a quarter to Renu.
∴ Number of sweets given to Renu =
.
Number of sweets given to Raji = 5.
Number of sweets left = 7.
According to the given condition,
(Transposing x to LHS and 12 to RHS)
(LCM of 1 and 4 is 4)
⇒ -3x = -12 × 4 (Transposing 4 to RHS)
-3x = -48
⇒ x =
(Transposing -3 to RHS)
x = 16
∴ The number of sweets that Sekhar had at the start is 16.
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