Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has 7 sweets left. How many did he have to start with?
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Answer:
Sekhar= x sweets
5+7 gives us the remaining three forth part of the sweets . As Renu has one forth part .
(3x/4) =12...
x= 12×4 /3
x=16
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