Select and write the most appropriate alternative from those provided
in the bracket :
1
If PA and PB are two tangent segments to a circle with centre o
such that APB = 62° then AOB = .
62°, 31°, 180°, 118)
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Answer:
Given PA & PB are tangent to the circle with center O.
PA=PB [length of tangent from external point to circle are equal]
In ΔPAB
PA=PB
∠PBA=∠PAB [isosceles triangle]
now ∠PAB+∠PBA+∠APB=180
o
[Angle sum prop]
2∠PAB=180−50=130
∠PBA=∠PAB=65
o
………..(1)
Now PA is tangent & OA is radius at point A.
∠OAP=90
o
[tangent at any point is ⊥ to radius]
∠OAB=∠OAP−∠PAB=90−65=25
o
Hence angle OAB is 25
o
.
Step-by-step explanation:
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