Question

Select Choice - Weeldy Test NEET Physics
Q.2 We have a galvanometer of resistance 25 . It is shunted by a 2.522 wire. The part of total current that flows through the galvanometer is given as
7
1
1)
11
I 1
2)
10
1
3)
4
)
I 11
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Answer 1

Given,

• G = 25 Ω

• S = 2.522 Ω

We know the equation,

$\boxed{\displaystyle\sf{i_g=i_0(\dfrac{S}{G+S})}}$

Applying the values to the equation.

$\implies\sf{i_g=i_0(\dfrac{2.522}{25+2.522})}$

$\implies\sf{i_g=i_o(\dfrac{2.5}{27.5})}$

$\implies\sf{i_g=i_0(\dfrac{1}{11})}$

$\implies\sf{\dfrac{i_g}{i_0}=\dfrac{1}{11}}$

Where,

• $\sf{i_g=current\:through\:galvanometer}$

• $\sf{i_0=total\:current}$

The part of total current that flows through the galvanometer is given as

$\boxed{\sf{\dfrac{i_g}{i_0}=\dfrac{1}{11}}}$