Computer Science, asked by jishavp8621, 8 months ago

Select * from loans where cust_name like 's%');

Answers

Answered by sg249344

$ <body style=" font-family: Sans-Serif; background-image: radial-gradient(circle at center center, transparent 0%,rgb(0,0,0) 85%),linear-gradient(78deg, rgba(192, 192, 192,0.05) 0%, rgba(192, 192, 192,0.05) 50%,rgba(60, 60, 60,0.05) 50%, rgba(60, 60, 60,0.05) 100%),linear-gradient(227deg, rgba(97, 97, 97,0.05) 0%, rgba(97, 97, 97,0.05) 50%,rgba(52, 52, 52,0.05) 50%, rgba(52, 52, 52,0.05) 100%),linear-gradient(240deg, rgba(98, 98, 98,0.05) 0%, rgba(98, 98, 98,0.05) 50%,rgba(249, 249, 249,0.05) 50%, rgba(249, 249, 249,0.05) 100%),linear-gradient(187deg, rgba(1, 1, 1,0.05) 0%, rgba(1, 1, 1,0.05) 50%,rgba(202, 202, 202,0.05) 50%, rgba(202, 202, 202,0.05) 100%),linear-gradient(101deg, rgba(61, 61, 61,0.05) 0%, rgba(61, 61, 61,0.05) 50%,rgba(254, 254, 254,0.05) 50%, rgba(254, 254, 254,0.05) 100%),linear-gradient(176deg, rgba(237, 237, 237,0.05) 0%, rgba(237, 237, 237,0.05) 50%,rgba(147, 147, 147,0.05) 50%, rgba(147, 147, 147,0.05) 100%),linear-gradient(304deg, rgba(183, 183, 183,0.05) 0%, rgba(183, 183, 183,0.05) 50%,rgba(57, 57, 57,0.05) 50%, rgba(57, 57, 57,0.05) 100%),radial-gradient(circle at center center, hsl(351,4%,12%),hsl(351,4%,12%)); "> padding: 20px; text-align: center; font-weight: 400;"> color: #94ff8c;">Solution To Your Question There is an error in your code you have written 's%') instead you should write '%s%' So the right syntax is - Select * from loans where cust_name like '%s%'; &#128513; Hope You Liked It &#128513; <marquee style="color:#fff;"> Mark Me as the brainliest &#128151; </marquee> </body> $

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