Physics, asked by wcayush4443, 11 months ago

Select One Option Correct from the following : A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cylinder is V and mass M . It is suspended by a string in a liquid of density \rho, where it stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. The force on the bottom of the cylinder by the liquid is
(A) Mg
(B) Mg-V \rho g
(C) Mg+\pi R^2 h \rho g
(D) \rho g(V+\pi R^2 h)

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Answered by Anonymous
4
b option is correct.
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Answered by UrvashiBaliyan
3

radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cylinder is V and mass M . It is suspended by a string in a liquid of density \rho, where it stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. The force on the bottom of the cylinder by the liquid is

(A) Mg

✔️(B) Mg-V \rho g

(C) Mg+\pi R^2 h \rho g

(D) \rho g(V+\pi R^2 h)

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