Physics, asked by sunnyyy5781, 10 months ago

Select One Option Correct from the following : A particle P is sliding down a frictionless Q hemispherical bowl. It passes the point A at \upsilon. A bead Q of the same mass as P is ejected from A at t = 0 along the horizontal string AB, with the speed \upsilon. Friction between the bead and the string may be neglected. Let t_P and t_Q be the respective times taken by P and Q to reach the point B. Then,
(A) t_P\  \textless \ t_Q (B) t_P=t_Q(C) t_P\  \textgreater \ t_Q(D) \frac{t_P}{t_Q} = \frac{length \ of \ arc \ ACB}{length \ of \ chord AB}

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Answered by Anonymous
0
a option is correct.
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Answered by UrvashiBaliyan
1

Select One Option Correct from the following : A particle P is sliding down a frictionless Q hemispherical bowl. It passes the point A at \upsilon. A bead Q of the same mass as P is ejected from A at t = 0 along the horizontal string AB, with the speed \upsilon. Friction between the bead and the string may be neglected. Let t_P and t_Q be the respective times taken by P and Q to reach the point B. Then,

✔️(A) t_P\ \textless \ t_Q (B) t_P=t_Q(C) t_P\ \textgreater \ t_Q(D) \frac{t_P}{t_Q} = \frac{length \ of \ arc \ ACB}{length \ of \ chord AB}

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