Question

Select One Option Correct from the following : A proton has kinetic energy E = 100 keV which is equal to energy of a photon. Let $\lambda_1$ be the de-Broglie wavelength of the proton and $\lambda_2$ be the wavelength of the photon. The ratio $\lambda_1/ \lambda_2$is proportional to
(A) $E^0$
(B) $E^{1/2}$
(C) $E^{-1}$
(D) $E^{-2}$

Answer 1

Answer:

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Explanation: