Physics, asked by omeir9295, 11 months ago

Select One Option Correct from the following :The dimensions of \frac{1}{2} \epsilon_0E^2 (where \epsilon_0 is permittivity of free space and E is electric field) is
(A) [MLT^{-1}]
(B) [ML^2T^{-2}]
(C) [ML^{-1}T^{-2}]
(D) [ML^2T{-1}]

Answers

Answered by luckiest1
0

\huge\bold\pink{hello!!}

HERE IS UR ANSWER

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✔✔[ML^{-1}T^{-2}]

Option C is correct

Thanks.

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