Question

Select One Option Correct from the following : The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment the displacement of the wire is $y_1 = A \sin (\pi x/L) \sin \omega t$ and energy is $E_1$ and in other experiment its displacement is $y_2 = A \sin (2\pi x/L) \sin 2\omega t$and energy is $E_2$. Then,
(A) $E_2=E_1$
(B) $E_2=2E_1$
(C) $E_2=4E_1$
(D) $E_2=16E_1$

Answer 1

c option is correct.
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Answer 2

Select One Option Correct from the following : The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment the displacement of the wire is $y_1 = A \sin (\pi x/L) \sin \omega t$ and energy is $E_1$ and in other experiment its displacement is $y_2 = A \sin (2\pi x/L) \sin 2\omega t$and energy is $E_2$. Then,

(A) $E_2=E_1$

(B) $E_2=2E_1$

✔️ (C) $E_2=4E_1$

(D) $E_2=16E_1$