Question

Select the correct answer from each drop-down menu.
Shape I is similar to shape II.
The sequence of transformations applied to shape I that proves shape I is similar to shape II is a reflection across the , and then a dilation by a scale factor of .

Answer 1

Answer:

I don't understand this guy's answers above me, could someone explain?

Step-by-step explanation:

Answer 2

Answer:

The correct answer from the drop-down menu

The scale factor is 1.5

Step-by-step explanation:

Given:

• Shape I is similar to shape II.

• The sequence of transformations applied to shape I that proves shape I is similar to shape II

Find:

To find the correct answer from each drop-down menu.

Shape I is similar to shape II.

The sequence of transformations applied to shape I that proves shape I is similar to shape II is a reflection across the, and then a dilation by a scale factor of.

Step 1:

The complete statement is:

The sequence of transformations applied to shape I that proves shape I is similar to shape II is a reflection across the y-axis, and then a dilation by a scale factor of 1.5.

From the figure, we can see that both shapes are on either side of the vertical axis.

Step 2

This means that:

The shape I is reflected across the y-axis.

Also, the measures of one of the corresponding sides of both shapes are:

Shape I = 2

Shape II = 3

Step 3

So, the scale factor is:

$\mathbf{k}=\frac{\text { Shape II }}{\text { Shape I }}$

This gives

$\mathbf{k}=\frac{3}{2}$

$\mathbf{k}=1.5$

Hence, the scale factor is 1.5

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