Question

Select the correct statement for Ne.
(A) It is not isoelectronic wih H,O
(B) Its last electron enters in S orbital
(C) The value of m must be zero for the last electron.
(D) The value of I must be 1 for the last electron.

with brief explanation (why) ?
every year jee main question​

Answer 1

Answer:

P with atomic number 15 with electronic configuration [Ne]3s

2

3p

3

contains 3 unpaired electrons.

(b) Si with atomic number 16 with electronic configuration [Ne]3s

2

3p

2

contains 2 unpaired electrons.

(c) Cr with atomic number 24with electronic configuration [Ar]3d

5

4s

1

contains 6 unpaired electrons.

(d) Fe with atomic number 26 with electronic configuration [Ar]3d

6

4s

2

contains 4 unpaired electrons.

(e) Kr with atomic number36 [Ar]3d

10

4s

2

4p

6

contains 0 unpaired electrons.