Select the option in which number of oxygen atoms is maximum 0.2 mol CO2(g) 22 g CO2(9) 112 ml CO2(g) at STP 0.02 g-molecules CO2(g)
Answers
we have to select the option in which the number of oxygen atoms is maximum.
solution : option (1) 0.2 mol of CO2
no of oxygen atoms in CO2 = no of moles of CO2 × no of oxygen atoms in a molecule of CO2 × N [ where N is abogadro's number ]
= 0.2 × 2 × N = 0.4 N
option (2) 22g of CO2
no of oxygen atoms = no of moles of CO2 × no of oxygen atoms in a molecule of CO2 × N
= 22g/44g/mol × 2 × N = 1N
option (3) 112 ml of CO2
no of oxygen atoms = no of moles of CO2 × no of oxygen atoms in a molecule of CO2 × N
= 112ml/22400ml × 2 × N = 0.01N
option (4) 0.02 g mole of CO2
no of oxygen atoms = no of moles of CO2 × no of oxygen atoms in a molecule of CO2 × N
= 0.02 × 2 × N = 0.04 N
from above explanation it is clear that no of oxygen atoms is maximum in option (2) 22g of CO2