Question

selling price of a commodity is rupee 15,600 .the profit earned is 30%.find.a cp and b profit earned
​

Answer 1

Solution :

$\underline{\bf{Given\::}}}}$

• Selling price of a commodity = Rs.15600
• Profit earned = 30%

$\underline{\bf{To\:find\::}}}}$

The cost price & profit earned.

$\underline{\bf{Explanation\::}}}}$

$\bigstar$ using formula of the Cost price when gained :

$\boxed{\bf{C.P.=\frac{100}{(100+gain\%)} \times S.P.}}}}$

$\longrightarrow\sf{C.P.=\dfrac{100}{100+30} \times 15600}\\\\\\\longrightarrow\sf{C.P.=\dfrac{100}{\cancel{130}} \times\cancel{ 15600}}\\\\\\\longrightarrow\sf{C.P.=Rs.(100\times 120)}\\\\\longrightarrow\bf{C.P.=Rs.12000}$

Now;

We know that formula of the profit :

$\longrightarrow\sf{Profit=Selling\:price-Cost\:price}\\\\\longrightarrow\sf{Profit=Rs.15600-Rs.12000}\\\\\longrightarrow\bf{Profit=Rs.3600}$

Answer 2

GIVEN :–

• Selling price = 15,600 rupees

• Earned profit = 30 %

TO FIND :–

(a) Cost price = ?

(b) Earned profit = ?

SOLUTION :–

$\\ \longrightarrow \large { \boxed{ \bold{Cost \: \: price = Selling \: \: price \: \: \pm \: Loss/Profit \: Money}}}$

• Let Cost price = 'x'

• Profit on cost price –

$\\ \implies { \bold{Profit = \dfrac{x \times 30}{100} }}$

• So that –

$\\ \implies { \bold{x = 15600 - \dfrac{x \times 30}{100} }}$

$\\ \implies { \bold{x + \dfrac{30x}{100} = 15600 }}$

$\\ \implies { \bold{\dfrac{130x}{100} = 15600 }}$

$\\ \implies { \bold{x= \dfrac{15600 \times 100}{130}}}$

$\\ \implies { \bold{x= \dfrac{1560000}{130}}}$

$\\ \implies {{ \bold{x= 12,000}}}$

$\\ \implies \large { \boxed { \bold{Cost \: \: price= 12,000 \: \: \: Rs}}}$

• Now Profit –

$\\ \implies { \bold{Profit = \dfrac{12,000 \times 30}{100} }}$

$\\ \implies { \bold{Profit = \dfrac{360000}{100} }}$

$\\ \implies \large {\boxed { \bold{Profit = 3,600 \: \: rs}}}$