Question

Sellioul - D
Derive the expression for Current density ( ) in terms of conductivity of the cont
(a) and electric field ( 2 ) applied across the conductor.
hoben hole1​

Answer 1

Answer:

 

Explanation:

Let 'I' current flow through a conductor when applied potential difference 'V' volt then, from ohm’s law,

I=V/R and R=ρL/A

I=VA/ρL

(I/A)=(V/L)*(1/ρ)

J=Eσ Where, Current density is J (=I/A), Electric field is E (=V/L), Resistivity is ρ and Conductivity is σ (=1/ρ)