Question

selve (x-3)^2=4 by facterization​

Answer 1

Answer:

x²+9-6x=4

x²-6x+5=0

x²-5x-x+5=0

x(x-5)-1(x-5)=0

(x-5)(x-1)=0

x=5 or x=1

Answer 2

Answer:

1 or 5

Step-by-step explanation:

${(x - 3)}^{2} = 4 \\ {(x - 3)}^{2} - {2}^{2} = 0 \\ (x - 3 + 2)(x - 3 - 2) = 0 \\ (x - 1)(x - 5) = 0 \\ x = 1 \: or \: x = 5$

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