Question

Sem oy
Find the equation.
Debebetale
find the equadratic equation whose roots are twice
root of 2x²-5x+2=0​

Answer 1

Answer:

solution :

solution :2x2 -5x +2 =0

solution :2x2 -5x +2 =02x2 -4x -x +2 =0

solution :2x2 -5x +2 =02x2 -4x -x +2 =02x( x -2 ) -1( x -2 ) =0

solution :2x2 -5x +2 =02x2 -4x -x +2 =02x( x -2 ) -1( x -2 ) =02x -1 =0 and x -2=0

solution :2x2 -5x +2 =02x2 -4x -x +2 =02x( x -2 ) -1( x -2 ) =02x -1 =0 and x -2=0 so x =1/2 and x =2

solution :2x2 -5x +2 =02x2 -4x -x +2 =02x( x -2 ) -1( x -2 ) =02x -1 =0 and x -2=0 so x =1/2 and x =2mark it as brainliest