Question

semi interquartile range of the data 3,4,6,9,11,12,14,15.

Answer 1

Hi,

➡️Answer: 4
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➡️Solution:

To find Interquartile range of 3,4,6,9,11,12,14,15

1) Arrange the data in ascending order

3,4,6,9,11,12,14,15

2) Find median of the data,for that count number of data points ; n = 8

Median of even number: average of n/2 th and n/2 +1 th term

n/2 = 4 th term = 9

n/2+1 = 5th term = 11

Median = (9+11)/2

= 10

Now Quartile 1, left part of median = (4+6)/2 = 5
Quartile 3,right part of median = (12+14)/2 = 13

➡️ISR =(Quartile 3- Quartile 1)/2

= (13-5)/2

= 8/2

= 4
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Hope it helps you.