English, asked by Raunakpreetkaur, 3 months ago

Semi-perimeter of the triangle, s=2a+b+c​

Area of triangle  =s(s−a)(s−b)(s−c)​.

When each side is doubled, the new sides are 2a,2b,2c. 
Hence, new s′=22a+2b+2c​=2(2a+b+c​)=2s
New area A′=2s(2s−2a)(2s−2b)(2s−2c)​

=2×2×2×2×s(s−a)(s−b)(s−c)​

=4s(s−a)(s−b)(s−c)​.

∴ % change in Area =AA′−A​×100

=s(s−a)(s−b)(s−c)​4s(s−a)(s−b)(s−c)​−s(s−a)(s−b)(s−c)​

Answers

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