Question

Semicircle of radius 12cm. Find the perimeter of the figure in terms of pi.

Answer 1

Given :

• Radius of Semi-Circle = 12 cm

To find :

• the perimeter of the semicircle.

Solution :

⇒ Let's find the Perimeter of Semicircle.

$\sf \longrightarrow Perimeter \: of \: Semicircle = \dfrac{1}{2} \pi d$

→ Here,

• π = 22/7
• d = 24 cm (∵ 12 × 2 = 24 cm)

$\sf \longrightarrow Perimeter \: of \: Semicircle = \dfrac{1}{2} \pi d$

$\sf \longrightarrow Perimeter \: of \: Semicircle = \dfrac{1}{2} \times \dfrac{22}{7} \times 24$

$\sf \longrightarrow Perimeter \: of \: Semicircle = \dfrac{1}{2} \times \dfrac{2 2 \times 24}{7}$

$\sf \longrightarrow Perimeter \: of \: Semicircle = \dfrac{1}{2} \times \dfrac{528}{7}$

$\sf \longrightarrow Perimeter \: of \: Semicircle = \dfrac{1 \times 528}{2 \times 7}$

$\sf \longrightarrow Perimeter \: of \: Semicircle = \dfrac{528}{14}$

$\sf \longrightarrow Perimeter \: of \: Semicircle = \dfrac{528}{14}$

$\sf = 37.71 cm^2$

• Therefore, the perimeter of the semicircle is 37.71 cm².

Answer 2

Question :-

Semicircle of radius 12cm. Find the perimeter of the figure in terms of pi.

Solution :-

Given :

• Radius (r) = 12cm
• π = $\rm{ \frac{22}{7} }$

Need to find :

• Perimeter of semicircle

Required Formula :

${\red{\boxed{\rm{Perimeter_{(Semicircle)} = \frac{1}{2} × \pi × d }}}}$

Here, we have only radius but in the formula we need the diameter also we know diameter = 2 × Radius.

Diameter :

$\sf:\longmapsto{d = 2 \times 12} \\ \\ \sf:\longmapsto{} \bf \red{d = 24cm}$

Now,

$\sf:\longmapsto{ \frac{1}{2} \times \frac{22}{7} \times 24 } \\ \\ \sf:\longmapsto{ \frac{22 \times 24}{14} } \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{ \frac{528}{14} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bf:\longmapsto \red{37.71} \: \: \: \: \: \: \: \: \: \:$

The $\sf{Perimeter_{(Semicircle)} }$ is 37.71cm².

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1. Find the perimeter of adjoining figure of semicircle take Pi equals 3.14 and diameter 20.

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