Question

semiconductor has an electron concentration of m–3 and a hole concentration of . calculate its conductivity.

Answer 1

The conductivity σ=e(ncμc+nhμh)

⇒σ=1.6×10−19(0.45×1022×0.135+5×1020×0.048)

⇒σ=3.85Ω−1m−1

Answer 2

Explanation:

conductivity is given by e(ncuc+nhuh)

where u=meu.

substitute and you will get answers.