Question

- sen
Show that i cos418. - sin 42 = 0
=0.​

Answer 1

Step-by-step explanation:

Given that:

Cos 418°-Sin42°

=>Cos(360°+58°)- Sin 42°

We know that Cos (360°+A)= Cos A

=>Cos58°-Sin42°

=>Cos (90°-42°)-Sin42°

We know that Cos (90°-A)=Sin A

=>Sin 42°-Sin42°

=>0

Cos 418°- Sin 42° = 0

Answer 2

Answer:

C 0 is the answer for your question