Question

senA. (1-sinA) (secA+tanA)=1​

Answer 1

Step-by-step explanation:

secA (1-sinA) (secA + tan A)  

= (secA-sinA×secA)(secA+tanA)

=(secA-tanA) (secA+tanA)  as secA=1/cosA and sinA/cosA=tanA

= (sec²A-tan²A) as (a+b)(a-b)=a²-b²

=sec²A-tan²A=1 from identity.

Hence proved.

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