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First find the volume of 1 gulab jamun.... Then find the 30% of it.. The answer multiply by 21... You will get the answer
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Volume of 1 hemisphere part =
2/3 × π × r ^3
( d = 2, r = 1)
= 2/3π
Volume of 2 hemispherical parts = 4/3π
Volume of cylindrical part
= πr^2h
( h = 2, r = 1 )
= 2π
Adding all Volumes
4/3π+2π
= 10π/3
Volume of liquid sugar = 30% of total volume
= 10π/3×30/100
= π
Volume of liquid sugar in 21 gulabjamuns
= 21π = 21×22/7 = 66cm^3
Regards
2/3 × π × r ^3
( d = 2, r = 1)
= 2/3π
Volume of 2 hemispherical parts = 4/3π
Volume of cylindrical part
= πr^2h
( h = 2, r = 1 )
= 2π
Adding all Volumes
4/3π+2π
= 10π/3
Volume of liquid sugar = 30% of total volume
= 10π/3×30/100
= π
Volume of liquid sugar in 21 gulabjamuns
= 21π = 21×22/7 = 66cm^3
Regards
VarunGupta11:
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