send me all question solution of exercise 8.2 of chapter 8 ncert class 8 maths . i will give you many more points
Answers
Answer:
1. A man got 10% increase in his salary. If his new salary is Rs.1,54,000, find his original salary.
Ans. Let original salary be Rs.100.
Therefore New salary i.e., 10% increase
= 100 + 10 = Rs.110
New salary is Rs.110, when original salary = Rs.100
New salary is Rs.1, when original salary =
New salary is Rs.1,54,000, when original salary = = Rs.1,40,000
Hence original salary is Rs. 1,40,000.
NCERT Solutions for Class 8 Maths Exercise 8.2
2. On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the percent decrease in the people visiting the Zoo on Monday?
Ans. On Sunday, people went to the Zoo
= 845
On Monday, people went to the Zoo = 169
Number of decrease in the people
= 845 – 169 = 676
Decrease percent = = 80%
Hence decrease in the people visiting the Zoo is 80%.
3. A shopkeeper buys 80 articles for Rs.2,400 and sells them for a profit of 16%. Find the selling price of one article.
Ans. No. of articles = 80
Cost Price of articles = Rs. 2,400And Profit
= 16%
Cost price of articles is Rs.100, then selling price = 100 + 16 = Rs.116
Cost price of articles is Rs.1, then selling price =
Cost price of articles is Rs.2400, then selling price = = Rs.2784
Hence, Selling Price of 80 articles = Rs.2784
Therefore Selling Price of 1 article
= = Rs.34.80
4. The cost of an article was Rs.15,500, Rs.450 were spent on its repairs. If it sold for a profit of 15%, find the selling price of the article.
Ans. Here, C.P. = Rs.15,500 and Repair cost = Rs.450
Therefore Total Cost Price = 15500 + 450 = Rs.15,950
Let C.P be Rs.100, then S.P. = 100 + 15
= Rs.115
When C.P. is Rs.100, then S.P. = Rs.115
When C.P. is Rs.1, then S.P. =
When C.P. is Rs.15950, then S.P.
= = Rs.18,342.50
NCERT Solutions for Class 8 Maths Exercise 8.2
5. A VCR and TV were bought for Rs.8,000 each. The shopkeeper made a loss of 4% on the VCR and a profit of 8% on the TV. Find the gain or loss percent on the whole transaction.
Ans. Cost price of VCR = Rs.8000 and Cost price of TV = Rs.8000
Total Cost Price of both articles
= Rs.8000 + Rs.8000 = Rs. 16,000
Now VCR is sold at 4% loss.
Let C.P. of each article be Rs.100, then S.P. of VCR = 100 – 4 = Rs.96
When C.P. is Rs.100, then S.P. = Rs.96
When C.P. is Rs.1, then S.P. =
When C.P. is Rs.8000, then S.P.
= = Rs.7,680
And TV is sold at 8% profit, then S.P. of TV = 100 + 8 = Rs.108
When C.P. is Rs.100, then S.P. = Rs.108
When C.P. is Rs.1, then S.P. =
When C.P. is Rs.8000, then S.P.
= = Rs.8,640
Then, Total S.P.
= Rs.7,680 + Rs.8,640 = Rs. 16,320
Since S.P. >C.P.,
Therefore Profit = S.P. – C.P.
= 16320 – 16000 = Rs.320
And Profit% =
== 2%
NCERT Solutions for Class 8 Maths Exercise 8.2
6. During a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at Rs.1450and two shirts marked at Rs.850 each?
Ans. Rate of discount on all items = 10%
Marked Price of a pair of jeans = Rs.1450 and Marked Price of a shirt = Rs.850
Discount on a pair of jeans
= = Rs.145
S.P. of a pair of jeans = Rs.1450 – Rs.145
= Rs.1305
Marked Price of two shirts =
= Rs.1700
Discount on two shirts =
= Rs.170
S.P. of two shirts = Rs.1700 – Rs.170
= Rs.1530
Therefore the customer had to pay
= 1305 + 1530
= Discount on a pair of jeans
=
= Rs.145
S.P. of a pair of jeans
= Rs.1450 – Rs.145 = Rs.2,835
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Answer:
Ex 8.2 Class 8 Maths Question 1.
A man got a 10% increase in his salary. If his new salary is ₹ 1,54,000, find his original salary.
Solution:
The increased salary = ₹ 1,54,000
Increase in salary = 10%
Increase salary = Original salary × (1 + [latex]\frac { Increase }{ 100 }[/latex])
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q1
Hence, the original salary = ₹ 1,40,000
Ex 8.2 Class 8 Maths Question 2.
On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the per cent decrease in the people visiting the Zoo on Monday?
Solution:
Number of people visiting the Zoo on Sunday = 845
Number of people visiting the Zoo on Monday = 169
Decrease in number of people visiting the Zoo = 845 – 169 = 676
Decrease per cent
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q2
Hence, the decrease per cent = 80%
Ex 8.2 Class 8 Maths Question 3.
A shopkeeper buys 80 articles for ₹ 2,400 and sells them for a profit of 16%. Find the selling price of one article.
Solution:
Cost price of 80 articles = ₹ 2,400
Cost of 1 article = ₹ [latex]\frac { 2400 }{ 80 }[/latex] = ₹ 30
Profit = 16%
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q3
Hence, the selling price of one article = ₹ 34.80
Ex 8.2 Class 8 Maths Question 4.
The cost of an article was ₹ 15,500. ₹ 450 were spent on its repairs. If it is sold for a profit of 15%, find the selling price of the article.
Solution:
CP of the article = ₹ 15,500
Money spent on repairs = ₹ 450
Net CP = ₹ 15,500 + ₹ 450 = ₹ 15,950
Profit = 15%
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q4
Hence, the selling price of article = ₹ 18342.50
Ex 8.2 Class 8 Maths Question 5.
A VCR and TV were bought for ₹ 8,000 each. The shopkeeper made a loss of 4% on the VCR and a profit of 8% on the TV. Find the gain or loss per cent on the whole transaction.
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q5
Solution:
Cost price of a VCR = ₹ 8,000
Loss = 4%
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q5.1
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q5.2
Hence, the shopkeeper gained 2% profit on the whole transaction.
Ex 8.2 Class 8 Maths Question 6.
During a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of Jeans marked at ₹ 1450 and two shirts marked at ₹ 850 each?
Solution:
Marked Price (MP) of Jeans = ₹ 1,450
MP of two shirts = ₹ 850 × 2 = ₹ 1,700
Total MP = ₹ 1,450 + ₹ 1,700 = ₹ 3,150
Discount = 10%
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q6
Thus, the customer will have to pay ₹ 2,835.
Ex 8.2 Class 8 Maths Question 7.
A milkman sold two of his buffaloes for ₹ 20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss. [Hint: Find CP of each]
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q7
Solution:
SP of a buffalo = ₹ 20,000
Gain = 5%
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q7.1
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q7.2
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q7.3
Ex 8.2 Class 8 Maths Question 8.
The price of a TV is ₹ 13,000. The sales tax charged on it is at the rate of 12%. Find the amount that Vinod will have to pay if he buys it.
Solution:
Marked price of the TV = ₹ 13,000
ST = 12%
NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Q8
The required amount that Vinod has to pay = ₹ 14,560
Ex 8.2 Class 8 Maths Question 9.
Arun bought a pair of skates at a sale where the discount is given was 20%. If the amount he pays is ₹ 1,600, find the marked price.
Solution:
Let the MP of the skates be ₹ 100
Discount = ₹ 20% of 100 = ₹ 20
Sale price = ₹ 100 – ₹ 20 = ₹ 80
If SP is ₹ 80 then MP = ₹ 100
If SP is ₹ 1 then MP = ₹ [latex]\frac { 100 }{ 80 }[/latex]
If SP is ₹ 1,600 then MP = ₹ [latex]\frac { 100 }{ 80 }[/latex] × 1600 = ₹ 2,000
Thus the MP = ₹ 2000.
Ex 8.2 Class 8 Maths Question 10.
I purchased a hair-dryer for ₹ 5,400 including 8% VAT. Find the price before VAT was added.
Solution:
Let the original price be ₹ 100
VAT = 8% of 100 = ₹ 8
Sale price = ₹ 100 + ₹ 8 = ₹ 108
If SP is ₹ 108 then original price = ₹ 100
If SP is ₹ 1 then the original price = ₹ [latex]\frac { 100 }{ 108 }[/latex]
If SP is ₹ 5,400 then the original price = ₹ [latex]\frac { 100 }{ 108 }[/latex] × 5,400 = ₹ 5,000
Thus, the price of hair-dryer before the addition of VAT = ₹ 5000.
Step-by-step explanation: