send me answer this sum
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here,put the formula cos 2x=2cos^2 x -1..
and sin 2x= 2 sin x . cos x
so, cot^-1 ((1+cos x)/sin x)
=cot^-1 ((2cos^2 x/2)/2sinx/2 .cosx/2)
=cot^-1((cos x/2)/sin x/2)
=cot^-1 (cot x/2)
=x/2
is the answer
and sin 2x= 2 sin x . cos x
so, cot^-1 ((1+cos x)/sin x)
=cot^-1 ((2cos^2 x/2)/2sinx/2 .cosx/2)
=cot^-1((cos x/2)/sin x/2)
=cot^-1 (cot x/2)
=x/2
is the answer
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sahil769:
thanks but i am confused. please send me photo to solved problem
Okk...wait
now...check the answer
2cos ^2x/2-x conditions i confused
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