Question

send me pic of answer​

Answer 1

$\huge{\mathcal{\blue{\underline{Answer}}}}$

$(x + y) {}^{2} = x {}^{2} + y {}^{2} + 2xy \\ (13) {}^{2} = x {}^{2} + y {}^{2} + 2(6 \times \frac{1}{4} ) \\ 169 = x {}^{2} + y {}^{2} + 2( \frac{25}{4} ) \\ 169 = x {}^{2} + y {}^{2} + \frac{25}{2} \\ 169 - \frac{25}{2} = x {}^{2} + y {}^{2} \\ \frac{169 \times 2 - 25}{2} = x {}^{2} + y {}^{2} \\ \frac{338 - 25}{2} = x {}^{2} + {y}^{2} \\ \frac{313}{2} = {x}^{2} + {y}^{2}$

Now using the identity

$(x - y) {}^{2} = x {}^{2} + y {}^{2} - 2(xy) \\ (x - y) {}^{2} = \frac{313}{2} - 2( \frac{25}{4} ) \\ (x - y) {}^{2} = \frac{313}{2} - \frac{25}{2} \\ (x - y ){}^{2} = \frac{313 - 25}{2} \\ (x - y) {}^{2} = \frac{288}{2} \\ (x - y) {}^{2} = 144 \\ x - y = \sqrt{144}$

$\huge{\mathcal{\blue{\implies{\underline{x-y=12}}}}}$

Answer 2

Answer:

hope it helps you......