Question

send me some basic formulas of trigonometry of 10th and 12th class@​

Answer 1

sin2+cos2=1

sec2=1+tan2

cosec2=1+cot2

Answer 2

Heya.....

Here's your answer......

   SinA = P / H

   CosA = B / H

   TanA = P / B

   CotA = B / P

   CosecA = H / P

   SecA = H/B

   Sin2A + Cos2A = 1

   Tan2A + 1 = Sec2A

     Cot2A + 1 = Cosec2A

   Sin (A +B) =SinA . CosB + CosA . SinB

   Sin (A – B) = SinA . CosB – CosA . SinB

   Cos (A + B) = CosA . CosB – SinA . SinB

   Cos (A – B) = CosA. CosB + SinA . SinB

   Tan (A + B) = TanA + TanB / 1 – TanA . TanB

   Tan (A – B) = TanA –TanB / 1 + TanA . TanB

   Sin ( A + B) . Sin (A – B) = Sin2A – Sin2B = Cos2B – Cos2A

   Cos (A + B) . Cos (A – B) = Cos2A – Sin2B = Cos2B – Sin2A

   Sin2A = 2 . SinA . CosA = 2 . TanA / (1 + Tan2A)

   Cos2A = Cos2A – Sin2A = 1 – 2Sin2A = 2Cos2A – 1 = (1 – Tan2A) / (1 + Tan2A)

   Tan2A = 2TanA / (1 – Tan2A)

    Sin3A = 3 . SinA – 4 . Sin3A

   Cos3A = 4 . Cos3A – 3 . CosA

   Tan3A = (3TanA – Tan3A) / (1 – 3Tan2A)

   SinA + SinB = 2 Sin (A + B)/2 Cos (A – B)/2

   SinA – SinB = 2 Sin (A – B)/2 Cos (A + B)/2

   CosA + CosB = 2 Cos(A – B)/2 Cos (A + B)/2

   CosA – CosB = 2 Sin(B – A)/2 Sin (A + B)/2

   TanA + TanB = Sin (A + B) / CosA . CosB

   SinA CosB = Sin (A + B) + Sin (A – B)

   CosA SinB = Sin (A + B) – Sin (A – B)

   CosA CosB = Cos (A + B) + Cos (A – B)

    SinA SinB = Cos (A – B) – Cos (A + B)

Thanks...!!!

XD

Sorry baby 'wink'