Question

send me the answer for these questions to check
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Answer 1

2-It has been given that

$\frac{2^{3x-1}+10}{7}=6$

Cross multiplying, we get

$2^{3x-1}+10=42$

Subtract 10 to both sides

$2^{3x-1}=32$

Write 32 in exponent form

$2^{3x-1}=2^5$

Since, base of both sides of the equation is 2. Hence, the exponent must be equal.

3x−1=5

Solve for x

$\begin{gathered}3x=6\\\\x=2\end{gathered}$