Math, asked by ambikaambi392, 8 months ago

send me the answer
write divisibility rule of the following ​

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Answers

Answered by Anonymous
3

Divisibility of 2 : last number should be even

Divisibility of 3 : last number should be odd

Divisibility of 4 : last two numbers should be divisible by 4 , So the whole number will be divisible by 4

divisibility of 5 : last digit should be 0 or 5

Divisibility of 8 : last two digit should be divisible by 8

Divisibility of 9 : number should be divisible by 3 and 6

Divisibility of 11 : it is based upon sum of odd and even places

Answered by sv305792
0

Answer:

if the last digit of NN is 2, 4, 6, 8, or 0;

\color{#20A900}{\boxed{\mathbf{3}}}

3

if the sum of digits of NN is a multiple of 3;

\color{#20A900}{\boxed{\mathbf{4}}}

4

if the last 2 digits of NN are a multiple of 4;

\color{#20A900}{\boxed{\mathbf{5}}}

5

if the last digit of NN is either 0 or 5;

\color{#20A900}{\boxed{\mathbf{6}}}

6

if NN is divisible by both 2 and 3;

\color{#20A900}{\boxed{\mathbf{7}}}

7

if subtracting twice the last digit of NN from the remaining digits gives a multiple of 7 (e.g. 658 is divisible by 7 because 65 - 2 x 8 = 49, which is a multiple of 7);

\color{#20A900}{\boxed{\mathbf{8}}}

8

if the last 3 digits of NN are a multiple of 8;

\color{#20A900}{\boxed{\mathbf{9}}}

9

if the sum of digits of NN is a multiple of 9;

\color{#20A900}{\boxed{\mathbf{10}}}

10

if the last digit of NN is 0;

\color{#20A900}{\boxed{\mathbf{11}}}

11

if the difference of the alternating sum of digits of NN is a multiple of 11 (e.g. 2343 is divisible by 11 because 2 - 3 + 4 - 3 = 0, which is a multiple of 11);

Step-by-step explanation:

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