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write divisibility rule of the following
Answers
Divisibility of 2 : last number should be even
Divisibility of 3 : last number should be odd
Divisibility of 4 : last two numbers should be divisible by 4 , So the whole number will be divisible by 4
divisibility of 5 : last digit should be 0 or 5
Divisibility of 8 : last two digit should be divisible by 8
Divisibility of 9 : number should be divisible by 3 and 6
Divisibility of 11 : it is based upon sum of odd and even places
Answer:
if the last digit of NN is 2, 4, 6, 8, or 0;
\color{#20A900}{\boxed{\mathbf{3}}}
3
if the sum of digits of NN is a multiple of 3;
\color{#20A900}{\boxed{\mathbf{4}}}
4
if the last 2 digits of NN are a multiple of 4;
\color{#20A900}{\boxed{\mathbf{5}}}
5
if the last digit of NN is either 0 or 5;
\color{#20A900}{\boxed{\mathbf{6}}}
6
if NN is divisible by both 2 and 3;
\color{#20A900}{\boxed{\mathbf{7}}}
7
if subtracting twice the last digit of NN from the remaining digits gives a multiple of 7 (e.g. 658 is divisible by 7 because 65 - 2 x 8 = 49, which is a multiple of 7);
\color{#20A900}{\boxed{\mathbf{8}}}
8
if the last 3 digits of NN are a multiple of 8;
\color{#20A900}{\boxed{\mathbf{9}}}
9
if the sum of digits of NN is a multiple of 9;
\color{#20A900}{\boxed{\mathbf{10}}}
10
if the last digit of NN is 0;
\color{#20A900}{\boxed{\mathbf{11}}}
11
if the difference of the alternating sum of digits of NN is a multiple of 11 (e.g. 2343 is divisible by 11 because 2 - 3 + 4 - 3 = 0, which is a multiple of 11);
Step-by-step explanation:
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