Question

Send me the full solution of Q3.

Answer 1

hey there here is your answer.....
$\frac{1}{1 - x} + \frac{1}{1 + x} + \frac{2}{1 + {x}^{2} } + \frac{4}{1 + {x}^{4} } + \frac{8}{1 + {x}^{8} } \\ \frac{(1 + x) + (1 - x)}{1 - {x}^{2} } + \frac{2}{1 + {x}^{2} } + \frac{4}{1 + {x}^{4} } + \frac{8}{1 + {x}^{8} } \\ \frac{2}{1 - {x}^{2} } + \frac{2}{1 + {x}^{2} } + \frac{4}{1 + {x}^{4} } + \frac{8}{1 + {x}^{8} } \\ similarly \\ \frac{4}{1 - {x}^{4} } + \frac{4}{1 + {x}^{4} } + \frac{8}{1 + {x}^{8} } \\ \frac{8}{1 - {x}^{8} } + \frac{8}{1 + {x}^{8 } } \\ = \frac{16}{1 - {x}^{16} }$
hope it helps...