Question

Send the answer of questions no 7 to 10 ​

Answer 1

Answer:

Step-by-step explanation:

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Q.10

let the centre of triangle be point O

and let D be point on circumference of given circle such that OD is radius of circle

here as triangle abc is a right angled triangle right angle at b

applying pythagoras theorem

we get

ab square+bc square=ac square

(6)square+(8)square=ac square

so ac square=64+36

=100

taking square roots on both sides

we get

ac=10 cm

here negative value would also be possible

but as dimensions length are never negative ac=-10 is absurd

thus ac=10 cm

so now then area of triangle abc=

1/2×ab×bc

=1/2×6×8

=48/2

=24 cm.

so thus area of triangle abc=24 cm.square

also perimeter of triangle abc=ab+bc+ac

=6+8+10

=24 cm

thus perimter of triangle abc=24 cm

so now as the adjoining circle is inscribed in triangle abc

we can defined it as an incircle

so thus OD is our inradius

so by using inradius formula

we get

Inradius =2×Area of circumscribed triangle/perimeter of circumscribed triangle

so OD=2×Area of triangle abc/perimeter of triangle abc

=2×24/24

=2cm

hence OD=2CM

thus radius of adjoining circle is 2cm

Answer 2

Answer:

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