Math, asked by xyz89, 1 year ago

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Answered by atul103
1
a − b) x + (a + b) y = a 2 − 2ab − b 2 … (1)

(a + b) (x + y) = a 2 + b 2

(a + b) x + (a + b) y = a 2 + b 2 … (2)

Subtracting equation (2) from (1), we obtain

(a − b) x − (a + b) x = (a 2 − 2ab − b 2) − (a 2 + b 2)

(a − b − a − b) x = − 2ab − 2b 2

− 2bx = − 2b (a + b)

x = a + b

Using equation (1), we obtain

(a − b) (a + b) + (a + b) y = a 2 − 2ab − b 2

a 2 − b 2 + (a + b) y = a 2− 2ab − b 2

(a + b) y = − 2ab

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