Question

send this question's full solution​

Answer 1

Answer:

Initial velocity (u) = 30 km/hr

Distance  (S) = 6 m = 0.006 km  

Final velocity (v) = 0 km/hr

$v^2 = u^2 +2aS \\0^2 = 30^2 + 2(a)(0.006)$

a . 0.012 = -900.00

a = -75000 km/h^2

Negative retardation represents retardation

Retardation (R) = 75000 km/hr^2

Retardation is doubled , a = -150000km/hr

Initial velocity = 60 km / hr

$v^2 = u^2 +2aS$

0 = (60)^2 + 2(-150000)S

300000.S = 3600

s = 3600/300000

S = 0.012 km

S =  12 m

ANSWER :- (2) 12m