Math, asked by AmoghRana, 4 months ago

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The internal and external diameters of a hollow hemispherical vessel are 24 cm and 25 cm, respectively. The total area to be painted is

(a)13211/7 cm²
(b)26961/14 cm²
(c) 6961/14 cm²
(d)16951/14 cm²​

Answers

Answered by shubham9588986203
0

Answer:

I don't think that answer of this question is answered in any of the options because

Step-by-step explanation:

If we want to find the total area of a hollow hemisphere then we will add it's outer curved area it's inner curved area and the area of the ring that is created when we intersect a hollow sphere .

so the curved area of outer/external curve will be. 2πr1^2

and the curved area of inner curve will be 2πr2^2

and the area of the ring (circular) =π(r1^2-r2^2)

So, the total surface area of hollow hemisphere will be 2π(r1^2+r2^2)+π(r1^2-r2^2)

So now we have the formula to calculate the area and we will implement it in our given question.

It is provided that

outer radius (r1) = 25 cm.

inner radius (r2) = 24 cm.

so TSA(Total Space Area) = 2π(25^2+24^2)+π(25^2-24^2)

2π(625+576)+π(625-576)

2π(1201)+π(49)

2402π+49π

2451π

53922/7 cm^2

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