Question

Separate 178 into two parts so that the first
part is 8 less than twice the second part.​

Answer 1

Answer:

Let the second part be 'x'  

Then the first part is 2x-8

By the problem,x+2x-8=178

3x-8=178

3x=178+8=186

x=186/3 = 62

So the first part is 2x-8 = 2(62)-8 = 124-8=116

Second part is x = 62

Answer 2

Answer:

178-(2x-8)=x

x=178-2x+8

3x=186

x=186/3

x=62

2x-8=124-8=116

Hope it helps you my dear friend