separate 178 into two parts so that the first part is 8 less than twice the second part
Answers
Answered by
4
Let the second part be a
First part = 2a - 8
According to question
a +2a - 8 = 178
=> 3a = 186
=> a = 62
First part = 116
Second part = 62
First part = 2a - 8
According to question
a +2a - 8 = 178
=> 3a = 186
=> a = 62
First part = 116
Second part = 62
Answered by
1
hiii!!!
here's ur answer...
given that the first part is 8 less than the twice of the second part.
therefore the second part be x.
and first part will be 2x-8
so x+2x-8 = 178
=> 3x-8 = 178
=> 3x = 178+8
=> 3x = 186
=> x = 186/3
=> x = 62
hence the second part = x
= 62
first part = 2x-8
= (2Γ62)-8
= 124-8
= 116
VERIFICATION:-
= 116+62
= 178
hence verified
hope this helps..!
here's ur answer...
given that the first part is 8 less than the twice of the second part.
therefore the second part be x.
and first part will be 2x-8
so x+2x-8 = 178
=> 3x-8 = 178
=> 3x = 178+8
=> 3x = 186
=> x = 186/3
=> x = 62
hence the second part = x
= 62
first part = 2x-8
= (2Γ62)-8
= 124-8
= 116
VERIFICATION:-
= 116+62
= 178
hence verified
hope this helps..!
Similar questions