Separate 178 into two parts so that the first part is 8 less than twice the second part
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Answered by
248
Let the second part be 'x'
Then the first part is 2x-8
By the problem,x+2x-8=178
3x-8=178
3x=178+8=186
x=186/3 = 62
So the first part is 2x-8 = 2(62)-8 = 124-8=116
Second part is x = 62
Then the first part is 2x-8
By the problem,x+2x-8=178
3x-8=178
3x=178+8=186
x=186/3 = 62
So the first part is 2x-8 = 2(62)-8 = 124-8=116
Second part is x = 62
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101
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