Question

separate 18 into two parts so that the first part is 3 less than twice the second part​

Answer 1

Answer:

• First part is 11.
• Second part is 7.

Step-by-step explanation:

Let us assume:

• Second part be x.

Then,

• First part is (2x - 3)

Solution:

Because,

18 is divided into x and (2x - 3).

Therefore,

$\sf{x+(2x-3)=18}$

Opening the bracket,

$\sf{x + 2x - 3 = 18}$

Transposing 3 from LHS to RHS and changing its sign,

$\sf{x+2x=18+3}$

Adding x and 2x ; 18 and 3,

$\sf{3x=21}$

Transposing 3 from LHS to RHS and changing its sign,

$\sf{x=\dfrac{21}{3}}$

Dividing 21 by 3,

$\sf{x=7}$

Hence, x = 7.

Therefore,

• Second part = x = 7
• First part = (2x - 3) = (2 × 7) - 3 = 14 - 3 = 11

Verification:

LHS:

7 + 11

= 18

RHS:

18

Hence, LHS = RHS.