Separate 3
√6 − √−12
into real and imaginary parts.
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Let `z=((3+sqrt(-1))/(2-sqrt(-1)))=((3+i)/(2-i))=((3+i)/(2-i))=((3+i))/((2-i))xx((2+i))/((2+i))`
`((3+i)(2+i))/((2-i)(2+i))=((6+i^(2))+5i)/((4-i^(2)))=(5+5i)/({4-(-1)})=(5(1+i))/(5)=(1+i)`.
`therefore" "|z|=sqrt(1^(2)+1^(2))=sqrt(2)`.
Hence, `z = (1 + i) and |z| = sqrt(2)`.
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