Question

separate and solve 6 square + 11b + 28​

Answer 1

Answer:

The first term is, b2 its coefficient is 1 .

The first term is, b2 its coefficient is 1 .The middle term is, -11b its coefficient is -11 .

The first term is, b2 its coefficient is 1 .The middle term is, -11b its coefficient is -11 .The last term, "the constant", is +28

The first term is, b2 its coefficient is 1 .The middle term is, -11b its coefficient is -11 .The last term, "the constant", is +28 Step-1 : Multiply the coefficient of the first term by the constant 1 • 28 = 28

The first term is, b2 its coefficient is 1 .The middle term is, -11b its coefficient is -11 .The last term, "the constant", is +28 Step-1 : Multiply the coefficient of the first term by the constant 1 • 28 = 28 Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is -11 .

The first term is, b2 its coefficient is 1 .The middle term is, -11b its coefficient is -11 .The last term, "the constant", is +28 Step-1 : Multiply the coefficient of the first term by the constant 1 • 28 = 28 Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is -11 . -28 + -1 = -29

The first term is, b2 its coefficient is 1 .The middle term is, -11b its coefficient is -11 .The last term, "the constant", is +28 Step-1 : Multiply the coefficient of the first term by the constant 1 • 28 = 28 Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is -11 . -28 + -1 = -29 -14 + -2 = -16

The first term is, b2 its coefficient is 1 .The middle term is, -11b its coefficient is -11 .The last term, "the constant", is +28 Step-1 : Multiply the coefficient of the first term by the constant 1 • 28 = 28 Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is -11 . -28 + -1 = -29 -14 + -2 = -16 -7 + -4 = -11 That's it