sequences and series!
Q:- the nth terms of the following two series are equal . find n:
(i) 5+10+20+-----
(ii) 1280+640+320+----
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the first one is in AP and the second one is in GP so equate the nth terms of the both
nth term of ap=a+(n-1)d
a=5,d=5 nth term is 5+(n-1)5=5+5n-5
nthe term of gp = a (r^n-1)/r-1
so we get a=1280 r=1/2
nth term is (1280 (1/2)^n-1)/1/2-1
now equate the both nth terms
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nth term of ap=a+(n-1)d
a=5,d=5 nth term is 5+(n-1)5=5+5n-5
nthe term of gp = a (r^n-1)/r-1
so we get a=1280 r=1/2
nth term is (1280 (1/2)^n-1)/1/2-1
now equate the both nth terms
mark as the brainllist answer
yelletipraneeth16:
Mark as the brainllist answer
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Question :-
Find the nth term of the following two series .
(1) 5 + 10 + 20 ..
Here first term ( a ) = 5 ,common difference (d) = 5
hence ,
→ it's nth term = a + ( n - 1) d
→ nth term = 5 + ( n - 1) 5
→ nth term = 5n
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