Question

Serena paid $194.99 for a game system and then bought two equally-priced games. She spent a total of $284.97.

Part A


If p represents the price of one game, which equation represents the situation?

1. 2p – 284.97 = 194.99

2. 2p + 194.99 = 284.97

3. 2p + 284.97 = 194.99

4. 2p – 194.99 = 284.97

Part B


What is the price, p, of one game?

$________ please help I'll mark you brainliest

Answer 1

SOLUTION

TO DETERMINE

Serena paid $194.99 for a game system and then bought two equally-priced games. She spent a total of $284.97.

Part A

If p represents the price of one game, which equation represents the situation?

1. 2p – 284.97 = 194.99

2. 2p + 194.99 = 284.97

3. 2p + 284.97 = 194.99

4. 2p – 194.99 = 284.97

Part B

What is the price, p, of one game?

EVALUATION

PART : A

Here it is given that Serena paid $ 194.99 for a game system and then bought two equally-priced games. She spent a total of $ 284.97

Now p represents the price of one game

So price of two equally-priced games = 2p

So Serena spent a total of = $ ( 2p + 194.99 )

Again it is also stated that She spent a total of $284.97

So by the given condition

2p + 194.99 = 284.97

Which is the required linear equation represents the situation

Hence the correct option is

2. 2p + 194.99 = 284.97

PART : B

We now solve for p

$\sf{2p + 194.99 = 284.97}$

$\sf{ \implies \: 2p = 284.97 - 194.99}$

$\sf{ \implies \: 2p = 89 .98}$

$\sf{ \implies \: p =44.99}$

Hence the required price of one game

= $ 44.99

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