Computer Science, asked by skatiyar2006, 10 months ago

Series -
1+2/1*2 + 1+2+3/1*2*3+..... 1+2+3+....n/1*2*3*.....n

Answers

Answered by sakshidabral27
2

Answer:

int i,j,sum=0,s=0,k=1;

for (i=2 ; i<=n ; i++)

{

for (j=1;j<=i;j++)

{

sum=sum+(s+j)/(k*j);

}

}

hope it helps!

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