Series -
1+2/1*2 + 1+2+3/1*2*3+..... 1+2+3+....n/1*2*3*.....n
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Answered by
2
Answer:
int i,j,sum=0,s=0,k=1;
for (i=2 ; i<=n ; i++)
{
for (j=1;j<=i;j++)
{
sum=sum+(s+j)/(k*j);
}
}
hope it helps!
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