Question

series 3,10,4,17,5,26,6,__

Answer 1

comsider series as 2 different series
A.P.1=3,4,5......
common difference 1

Series 2=10,17,26.....
common difference 7 is increasing by 2

Answer 2

answer is 37 ,,,,,,

as you can see the next term is of form ;;

(square of previous one +1)

3,(3^2)+1= 10
,,,4,(4^2)+1= 17

therefore last term will be (6)^2+1= 37