series 3,10,4,17,5,26,6,__
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comsider series as 2 different series
A.P.1=3,4,5......
common difference 1
Series 2=10,17,26.....
common difference 7 is increasing by 2
A.P.1=3,4,5......
common difference 1
Series 2=10,17,26.....
common difference 7 is increasing by 2
rohanrit:
ok
howw
??
the ans is correct i checked it but how did you got the ans
Answered by
4
answer is 37 ,,,,,,
as you can see the next term is of form ;;
(square of previous one +1)
3,(3^2)+1= 10
,,,4,(4^2)+1= 17
therefore last term will be (6)^2+1= 37
as you can see the next term is of form ;;
(square of previous one +1)
3,(3^2)+1= 10
,,,4,(4^2)+1= 17
therefore last term will be (6)^2+1= 37
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