Chemistry, asked by minor8769, 2 months ago

Seriously do not type or take points if you do not know I really need help please
What is the concentration of a solution made by adding 89 g CH4 to 300 L of water?
How many liters are needed to make a 9.6 M solution with 4.6 moles of MgO?
What is the molarity of a solution that contains 6 grams of N2 in 579 mL of solution?
What volume of 0.987 M solution can be prepared from 54.3 grams of NO2?

Answers

Answered by s02371joshuaprince47
0

Answer:

T = 27 + 273 = 300 K; torr. 10 x 87.1 atm 1 torr. 760. L 3.00. K). )(300. 10 x ... X(CH4) = mol. 10 x. 538.1 mol. 10 x. 7.79. 1-. -2. = 0.507. 5.88 Concentrations in parts per million

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Answered by MrNobody78
1

T= 27 + 273 = 300 K; torr. 10 x 87.1 atm 1 torr. 760. L 3.00. K). )(300. 10 x ... X(CH4) = mol. 10 x. 538.1 mol. 10 x. 7.79. 1-. -2. = 0.507. 5.88 Concentrations in parts per million

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