Question

SET-A [10] Using integration find the area of triangle with vertices
(5, 1), (5, 3) and (7,0).
(Ans. 2 Sq. units]​

Answer 1

Area of Triangle =  2 Sq. units with vertices (5, 1), (5, 3) and (7,0)

Step-by-step explanation:

(5, 1), (5, 3) and (7,0).

Area of Triangle = (1/2) | 5 (3 - 0)  + 5(0 - 1)  + 7( 1 - 3)|

= (1/2) | 15 - 5  - 14 |

= (1/2) | - 4|

= 4/2

= 2

Area of Triangle =  2 Sq. units

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