Set A,B and C are: A = {1, 2, 4, 8, 10 12,14}, B = { 1,2, 3 ,4, 5 }
and C { 2, 5,7,9,11, 13}.
Find A BC , A B C, A BC and (B~C)
Mecrin:
A intersection b union c, A union B union C,A union B intersection C and (B~C)
ok wait..
where are th brackets?[]{}(),
NO Brackets!!!!! Question is like that only
we can't solve it then..
What is the answer of this !!!!!!! (B~C)
{1,3,4} is the ans fr lst one
last one*
Okay!!!!!!!!!! Thank you so much
my pleasure
Answers
Answered by
1
A = { 1, 2, 4, 8, 10, 12, 14)
B = (1,2 , 3, 4, 5, }
C = { 2, 5, 7, 9, 11, 13 }
A ∧ B U C is probably either (A ∧ B) U C or A ∧ (B U C). Check question...
(A ∧ B) U C = {1, 2, 4} U C = {1, 2, 4, 5, 7, 9, 11, 13} --- (1)
A ∧ (B U C) = A ∧ {1, 2, 3, 4, 5, 7, 9, 11, 13} = {1, 2, 4} --- (2)
(1) is always a subset of (2)...
=====================
A U B U C = (A U B) U C = A U (B U C) both are same
= { 1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 12, 13, 14 }
=============
A U B∧ C
(A U B) ∧ C = {1, 2, 3, 4, 5, 8, 10, 12, 14 } ∧ C = { 2, 5 }
A U (B ∧ C) = A U {2, 5 } = {1, 2, 4, 5, 8, 10, 12, 14 }
=================
B - C = B - (B ∧ C) = { 1, 3, 4 }
B = (1,2 , 3, 4, 5, }
C = { 2, 5, 7, 9, 11, 13 }
A ∧ B U C is probably either (A ∧ B) U C or A ∧ (B U C). Check question...
(A ∧ B) U C = {1, 2, 4} U C = {1, 2, 4, 5, 7, 9, 11, 13} --- (1)
A ∧ (B U C) = A ∧ {1, 2, 3, 4, 5, 7, 9, 11, 13} = {1, 2, 4} --- (2)
(1) is always a subset of (2)...
=====================
A U B U C = (A U B) U C = A U (B U C) both are same
= { 1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 12, 13, 14 }
=============
A U B∧ C
(A U B) ∧ C = {1, 2, 3, 4, 5, 8, 10, 12, 14 } ∧ C = { 2, 5 }
A U (B ∧ C) = A U {2, 5 } = {1, 2, 4, 5, 8, 10, 12, 14 }
=================
B - C = B - (B ∧ C) = { 1, 3, 4 }
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no sir !!! but the question........ find A union B union C, A union B intersection C, and (B not equal c)
what i understood, i did...
Ya offcourse!!!! Thank you so much i am also confused. there is no brackets inbetween the these threee set!!!!!!
That is what I told,there is no brackets hence it becomes difficult to solve it.
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