Question

Set A has 3 elements and the set B has 4 elements. Then the number of injective functions that can be defined from set A to set B is *

12

24

64

5

​

Answer 1

Answer:

24

Step-by-step explanation:

it creates an order like

4,3,2,1 ....

so the answer will be

4×3×2×1

=24

Answer 2

ANSWER GIVEN BELOW

To define the injective functions from set A to set B, we can map the first element of set A to any of the 4 elements of set B.

Then the second element can not be mapped to the same element of set A, hence, there are 3 choices in set B for the second element of set A.

Similarly there are 2 choices in set B for the third element of set A.

Hence the total number of injective functions are 4×3×2=24