set a is equals to flower bracket x x belongs n and X is a multiple of 4 less than 20 flower bracket
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Answer:
A = {x:x is a natural number and multiple of 3} = {3,6,9…}
As, B = {x:x is a natural number less than 6} = {1,2,3,4,5,6}
A∪B = {1,2,4,5,3,6,9,12…}
∴, A∪B = {x:x=1,2,4,5 or a multiple of 3}
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Given, A={x:xisamultipleof4}
={4,8,12,16,20,…}
and B={x:xisamultipleof6}
={6,12,18,24,…}
∴A∩B={12,24,…}
={x:xisamultipleof12
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